Give reasons for the failure of the Bohr Model.
(N/A) The Bohr model fails for the following reasons:
$1$. It treats the electron as a charged particle and ignores the wave character of the electron.
$2$. It assumes that electrons move in well-defined circular orbits. According to the Heisenberg uncertainty principle,it is impossible to determine both the exact position and the exact velocity of an electron simultaneously.
$3$. The model ignores the dual behavior of matter and contradicts the Heisenberg uncertainty principle. Consequently,it cannot be extended to multi-electron atoms.
$1$. It treats the electron as a charged particle and ignores the wave character of the electron.
$2$. It assumes that electrons move in well-defined circular orbits. According to the Heisenberg uncertainty principle,it is impossible to determine both the exact position and the exact velocity of an electron simultaneously.
$3$. The model ignores the dual behavior of matter and contradicts the Heisenberg uncertainty principle. Consequently,it cannot be extended to multi-electron atoms.
Explore More
Similar Questions
When electronic transition occurs from a higher energy state to a lower energy state with an energy difference equal to $\Delta E$ electron volts,the wavelength of the emitted line is approximately equal to
Medium
View SolutionIf the wavelength of the limiting line of the Lyman series of the hydrogen atom is $16$ times the wavelength of the limiting line of the same series for an ion $X$,then what is $X$?
Medium
View SolutionThe ionization energy of $He^+$ is $19.6 \times 10^{-18} \ J \ atom^{-1}$. What is the energy of the first stationary state $(n = 1)$ of $Li^{2+}$?
Medium
View SolutionIn Rutherford's experiment,generally the thin foil of heavy atoms,like gold,platinum etc. have been used to be bombarded by the $\alpha$-particles. If the thin foil of light atoms like Aluminium etc. is used,what difference would be observed from the above results?
Medium
View SolutionThe total energy of the electron of $H$ atom in the second quantum state is $-E_2$. The total energy of the $He^{+}$ ion in the third quantum state is
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo